Arapahoe County, CO vs Sandoval County, NM
Property Tax Rate Comparison 2025
Quick Answer
Arapahoe County, CO: 0.56% effective rate · $4,031/yr median tax · median home $719,879
Sandoval County, NM: 0.84% effective rate · $1,304/yr median tax · median home $155,264
Side-by-Side Comparison
| Metric | Arapahoe County, CO | Sandoval County, NM | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.56% | 0.84% | 1.06% |
| Median Annual Tax | $4,031 | $1,304 | $2,778 |
| Median Home Value | $719,879 | $155,264 | $268,728 |
| Population | 655,070 | 148,834 | — |
Arapahoe County, CO
- Effective Rate
- 0.56%
- Median Annual Tax
- $4,031
- Median Home Value
- $719,879
- Population
- 655,070
Sandoval County, NM
- Effective Rate
- 0.84%
- Median Annual Tax
- $1,304
- Median Home Value
- $155,264
- Population
- 148,834
Frequently Asked Questions
What is the property tax difference between Arapahoe County and Sandoval County?
Arapahoe County, CO has an effective property tax rate of 0.56% with a median annual tax of $4,031. Sandoval County, NM has a rate of 0.84% with a median annual tax of $1,304. The difference is 0.28 percentage points.
Which county has higher property taxes, Arapahoe County or Sandoval County?
Sandoval County, NM has the higher effective property tax rate at 0.84% compared to 0.56%.
How do Arapahoe County and Sandoval County compare to the national average?
The national average effective property tax rate is 1.06%. Arapahoe County is below average at 0.56%, and Sandoval County is below average at 0.84%.