Broward County, FL vs Saginaw County, MI
Property Tax Rate Comparison 2025
Quick Answer
Broward County, FL: 0.88% effective rate · $3,539/yr median tax · median home $402,176
Saginaw County, MI: 1.28% effective rate · $1,903/yr median tax · median home $148,689
Side-by-Side Comparison
| Metric | Broward County, FL | Saginaw County, MI | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.88% | 1.28% | 1.06% |
| Median Annual Tax | $3,539 | $1,903 | $2,778 |
| Median Home Value | $402,176 | $148,689 | $268,728 |
| Population | 1,944,375 | 190,539 | — |
Broward County, FL
- Effective Rate
- 0.88%
- Median Annual Tax
- $3,539
- Median Home Value
- $402,176
- Population
- 1,944,375
Saginaw County, MI
- Effective Rate
- 1.28%
- Median Annual Tax
- $1,903
- Median Home Value
- $148,689
- Population
- 190,539
Frequently Asked Questions
What is the property tax difference between Broward County and Saginaw County?
Broward County, FL has an effective property tax rate of 0.88% with a median annual tax of $3,539. Saginaw County, MI has a rate of 1.28% with a median annual tax of $1,903. The difference is 0.40 percentage points.
Which county has higher property taxes, Broward County or Saginaw County?
Saginaw County, MI has the higher effective property tax rate at 1.28% compared to 0.88%.
How do Broward County and Saginaw County compare to the national average?
The national average effective property tax rate is 1.06%. Broward County is below average at 0.88%, and Saginaw County is above average at 1.28%.