Broward County, FL vs Sangamon County, IL
Property Tax Rate Comparison 2025
Quick Answer
Broward County, FL: 0.88% effective rate · $3,539/yr median tax · median home $402,176
Sangamon County, IL: 2.18% effective rate · $6,119/yr median tax · median home $280,700
Side-by-Side Comparison
| Metric | Broward County, FL | Sangamon County, IL | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.88% | 2.18% | 1.06% |
| Median Annual Tax | $3,539 | $6,119 | $2,778 |
| Median Home Value | $402,176 | $280,700 | $268,728 |
| Population | 1,944,375 | 197,661 | — |
Broward County, FL
- Effective Rate
- 0.88%
- Median Annual Tax
- $3,539
- Median Home Value
- $402,176
- Population
- 1,944,375
Sangamon County, IL
- Effective Rate
- 2.18%
- Median Annual Tax
- $6,119
- Median Home Value
- $280,700
- Population
- 197,661
Frequently Asked Questions
What is the property tax difference between Broward County and Sangamon County?
Broward County, FL has an effective property tax rate of 0.88% with a median annual tax of $3,539. Sangamon County, IL has a rate of 2.18% with a median annual tax of $6,119. The difference is 1.30 percentage points.
Which county has higher property taxes, Broward County or Sangamon County?
Sangamon County, IL has the higher effective property tax rate at 2.18% compared to 0.88%.
How do Broward County and Sangamon County compare to the national average?
The national average effective property tax rate is 1.06%. Broward County is below average at 0.88%, and Sangamon County is above average at 2.18%.