Broward County, FL vs Santa Fe County, NM
Property Tax Rate Comparison 2025
Quick Answer
Broward County, FL: 0.88% effective rate · $3,539/yr median tax · median home $402,176
Santa Fe County, NM: 0.58% effective rate · $741/yr median tax · median home $127,791
Side-by-Side Comparison
| Metric | Broward County, FL | Santa Fe County, NM | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.88% | 0.58% | 1.06% |
| Median Annual Tax | $3,539 | $741 | $2,778 |
| Median Home Value | $402,176 | $127,791 | $268,728 |
| Population | 1,944,375 | 154,823 | — |
Broward County, FL
- Effective Rate
- 0.88%
- Median Annual Tax
- $3,539
- Median Home Value
- $402,176
- Population
- 1,944,375
Santa Fe County, NM
- Effective Rate
- 0.58%
- Median Annual Tax
- $741
- Median Home Value
- $127,791
- Population
- 154,823
Frequently Asked Questions
What is the property tax difference between Broward County and Santa Fe County?
Broward County, FL has an effective property tax rate of 0.88% with a median annual tax of $3,539. Santa Fe County, NM has a rate of 0.58% with a median annual tax of $741. The difference is 0.30 percentage points.
Which county has higher property taxes, Broward County or Santa Fe County?
Broward County, FL has the higher effective property tax rate at 0.88% compared to 0.58%.
How do Broward County and Santa Fe County compare to the national average?
The national average effective property tax rate is 1.06%. Broward County is below average at 0.88%, and Santa Fe County is below average at 0.58%.