Howard County, MD vs San Joaquin County, CA
Property Tax Rate Comparison 2025
Quick Answer
Howard County, MD: 1.21% effective rate · $2,901/yr median tax · median home $239,785
San Joaquin County, CA: 0.64% effective rate · $3,258/yr median tax · median home $509,076
Side-by-Side Comparison
| Metric | Howard County, MD | San Joaquin County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 1.21% | 0.64% | 1.06% |
| Median Annual Tax | $2,901 | $3,258 | $2,778 |
| Median Home Value | $239,785 | $509,076 | $268,728 |
| Population | 332,317 | 779,233 | — |
Howard County, MD
- Effective Rate
- 1.21%
- Median Annual Tax
- $2,901
- Median Home Value
- $239,785
- Population
- 332,317
San Joaquin County, CA
- Effective Rate
- 0.64%
- Median Annual Tax
- $3,258
- Median Home Value
- $509,076
- Population
- 779,233
Frequently Asked Questions
What is the property tax difference between Howard County and San Joaquin County?
Howard County, MD has an effective property tax rate of 1.21% with a median annual tax of $2,901. San Joaquin County, CA has a rate of 0.64% with a median annual tax of $3,258. The difference is 0.57 percentage points.
Which county has higher property taxes, Howard County or San Joaquin County?
Howard County, MD has the higher effective property tax rate at 1.21% compared to 0.64%.
How do Howard County and San Joaquin County compare to the national average?
The national average effective property tax rate is 1.06%. Howard County is above average at 1.21%, and San Joaquin County is below average at 0.64%.