Johnson County, IA vs San Francisco County, CA
Property Tax Rate Comparison 2025
Quick Answer
Johnson County, IA: 1.80% effective rate · $3,193/yr median tax · median home $177,418
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Side-by-Side Comparison
| Metric | Johnson County, IA | San Francisco County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 1.80% | 0.72% | 1.06% |
| Median Annual Tax | $3,193 | $5,391 | $2,778 |
| Median Home Value | $177,418 | $748,790 | $268,728 |
| Population | 153,317 | 873,965 | — |
Johnson County, IA
- Effective Rate
- 1.80%
- Median Annual Tax
- $3,193
- Median Home Value
- $177,418
- Population
- 153,317
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Frequently Asked Questions
What is the property tax difference between Johnson County and San Francisco County?
Johnson County, IA has an effective property tax rate of 1.80% with a median annual tax of $3,193. San Francisco County, CA has a rate of 0.72% with a median annual tax of $5,391. The difference is 1.08 percentage points.
Which county has higher property taxes, Johnson County or San Francisco County?
Johnson County, IA has the higher effective property tax rate at 1.80% compared to 0.72%.
How do Johnson County and San Francisco County compare to the national average?
The national average effective property tax rate is 1.06%. Johnson County is above average at 1.80%, and San Francisco County is below average at 0.72%.