Medina County, OH vs San Francisco County, CA
Property Tax Rate Comparison 2025
Quick Answer
Medina County, OH: 2.01% effective rate · $3,625/yr median tax · median home $180,363
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Side-by-Side Comparison
| Metric | Medina County, OH | San Francisco County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 2.01% | 0.72% | 1.06% |
| Median Annual Tax | $3,625 | $5,391 | $2,778 |
| Median Home Value | $180,363 | $748,790 | $268,728 |
| Population | 182,470 | 873,965 | — |
Medina County, OH
- Effective Rate
- 2.01%
- Median Annual Tax
- $3,625
- Median Home Value
- $180,363
- Population
- 182,470
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Frequently Asked Questions
What is the property tax difference between Medina County and San Francisco County?
Medina County, OH has an effective property tax rate of 2.01% with a median annual tax of $3,625. San Francisco County, CA has a rate of 0.72% with a median annual tax of $5,391. The difference is 1.29 percentage points.
Which county has higher property taxes, Medina County or San Francisco County?
Medina County, OH has the higher effective property tax rate at 2.01% compared to 0.72%.
How do Medina County and San Francisco County compare to the national average?
The national average effective property tax rate is 1.06%. Medina County is above average at 2.01%, and San Francisco County is below average at 0.72%.