Polk County, FL vs Sandoval County, NM
Property Tax Rate Comparison 2025
Quick Answer
Polk County, FL: 0.92% effective rate · $2,334/yr median tax · median home $253,711
Sandoval County, NM: 0.84% effective rate · $1,304/yr median tax · median home $155,264
Side-by-Side Comparison
| Metric | Polk County, FL | Sandoval County, NM | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.92% | 0.84% | 1.06% |
| Median Annual Tax | $2,334 | $1,304 | $2,778 |
| Median Home Value | $253,711 | $155,264 | $268,728 |
| Population | 724,777 | 148,834 | — |
Polk County, FL
- Effective Rate
- 0.92%
- Median Annual Tax
- $2,334
- Median Home Value
- $253,711
- Population
- 724,777
Sandoval County, NM
- Effective Rate
- 0.84%
- Median Annual Tax
- $1,304
- Median Home Value
- $155,264
- Population
- 148,834
Frequently Asked Questions
What is the property tax difference between Polk County and Sandoval County?
Polk County, FL has an effective property tax rate of 0.92% with a median annual tax of $2,334. Sandoval County, NM has a rate of 0.84% with a median annual tax of $1,304. The difference is 0.08 percentage points.
Which county has higher property taxes, Polk County or Sandoval County?
Polk County, FL has the higher effective property tax rate at 0.92% compared to 0.84%.
How do Polk County and Sandoval County compare to the national average?
The national average effective property tax rate is 1.06%. Polk County is below average at 0.92%, and Sandoval County is below average at 0.84%.