Polk County, IA vs San Francisco County, CA
Property Tax Rate Comparison 2025
Quick Answer
Polk County, IA: 1.56% effective rate · $1,541/yr median tax · median home $98,831
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Side-by-Side Comparison
| Metric | Polk County, IA | San Francisco County, CA | National Avg |
|---|---|---|---|
| Effective Tax Rate | 1.56% | 0.72% | 1.06% |
| Median Annual Tax | $1,541 | $5,391 | $2,778 |
| Median Home Value | $98,831 | $748,790 | $268,728 |
| Population | 492,401 | 873,965 | — |
Polk County, IA
- Effective Rate
- 1.56%
- Median Annual Tax
- $1,541
- Median Home Value
- $98,831
- Population
- 492,401
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Frequently Asked Questions
What is the property tax difference between Polk County and San Francisco County?
Polk County, IA has an effective property tax rate of 1.56% with a median annual tax of $1,541. San Francisco County, CA has a rate of 0.72% with a median annual tax of $5,391. The difference is 0.84 percentage points.
Which county has higher property taxes, Polk County or San Francisco County?
Polk County, IA has the higher effective property tax rate at 1.56% compared to 0.72%.
How do Polk County and San Francisco County compare to the national average?
The national average effective property tax rate is 1.06%. Polk County is above average at 1.56%, and San Francisco County is below average at 0.72%.