San Francisco County, CA vs Sandoval County, NM
Property Tax Rate Comparison 2025
Quick Answer
San Francisco County, CA: 0.72% effective rate · $5,391/yr median tax · median home $748,790
Sandoval County, NM: 0.84% effective rate · $1,304/yr median tax · median home $155,264
Side-by-Side Comparison
| Metric | San Francisco County, CA | Sandoval County, NM | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.72% | 0.84% | 1.06% |
| Median Annual Tax | $5,391 | $1,304 | $2,778 |
| Median Home Value | $748,790 | $155,264 | $268,728 |
| Population | 873,965 | 148,834 | — |
San Francisco County, CA
- Effective Rate
- 0.72%
- Median Annual Tax
- $5,391
- Median Home Value
- $748,790
- Population
- 873,965
Sandoval County, NM
- Effective Rate
- 0.84%
- Median Annual Tax
- $1,304
- Median Home Value
- $155,264
- Population
- 148,834
Frequently Asked Questions
What is the property tax difference between San Francisco County and Sandoval County?
San Francisco County, CA has an effective property tax rate of 0.72% with a median annual tax of $5,391. Sandoval County, NM has a rate of 0.84% with a median annual tax of $1,304. The difference is 0.12 percentage points.
Which county has higher property taxes, San Francisco County or Sandoval County?
Sandoval County, NM has the higher effective property tax rate at 0.84% compared to 0.72%.
How do San Francisco County and Sandoval County compare to the national average?
The national average effective property tax rate is 1.06%. San Francisco County is below average at 0.72%, and Sandoval County is below average at 0.84%.