San Joaquin County, CA vs Vanderburgh County, IN
Property Tax Rate Comparison 2025
Quick Answer
San Joaquin County, CA: 0.64% effective rate · $3,258/yr median tax · median home $509,076
Vanderburgh County, IN: 0.71% effective rate · $1,018/yr median tax · median home $143,500
Side-by-Side Comparison
| Metric | San Joaquin County, CA | Vanderburgh County, IN | National Avg |
|---|---|---|---|
| Effective Tax Rate | 0.64% | 0.71% | 1.06% |
| Median Annual Tax | $3,258 | $1,018 | $2,778 |
| Median Home Value | $509,076 | $143,500 | $268,728 |
| Population | 779,233 | 181,451 | — |
San Joaquin County, CA
- Effective Rate
- 0.64%
- Median Annual Tax
- $3,258
- Median Home Value
- $509,076
- Population
- 779,233
Vanderburgh County, IN
- Effective Rate
- 0.71%
- Median Annual Tax
- $1,018
- Median Home Value
- $143,500
- Population
- 181,451
Frequently Asked Questions
What is the property tax difference between San Joaquin County and Vanderburgh County?
San Joaquin County, CA has an effective property tax rate of 0.64% with a median annual tax of $3,258. Vanderburgh County, IN has a rate of 0.71% with a median annual tax of $1,018. The difference is 0.07 percentage points.
Which county has higher property taxes, San Joaquin County or Vanderburgh County?
Vanderburgh County, IN has the higher effective property tax rate at 0.71% compared to 0.64%.
How do San Joaquin County and Vanderburgh County compare to the national average?
The national average effective property tax rate is 1.06%. San Joaquin County is below average at 0.64%, and Vanderburgh County is below average at 0.71%.